Blundell Thermal Physics · Problem 20.5

The partition function

Physics — Statistical Mechanics · spin-half-paramagnet-thermodynamics

Problem

Show that for NN non-interacting spin-12\frac{1}{2} particles in a magnetic field BB the energy UU is given by U=−NμBBtanh⁡(μBBkBT),(20.52)U = -N\mu_B B \tanh\left(\frac{\mu_B B}{k_B T}\right), \tag{20.52} the heat capacity is given by CNkB=(μBBkBT)2sech2(μBBkBT),(20.53)\frac{C}{Nk_B} = \left(\frac{\mu_B B}{k_B T}\right)^2 \mathrm{sech}^2\left(\frac{\mu_B B}{k_B T}\right), \tag{20.53} and the entropy is given by SNkB=ln⁡[2cosh⁡(μBBkBT)]−μBBkBTtanh⁡(μBBkBT).(20.54)\frac{S}{Nk_B} = \ln\left[2\cosh\left(\frac{\mu_B B}{k_B T}\right)\right] - \frac{\mu_B B}{k_B T}\tanh\left(\frac{\mu_B B}{k_B T}\right). \tag{20.54}

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