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Mathematics
Problem
Which of the following series is NOT suitable for analysis with an integral comparison starting at
n
=
1
n=1
n
=
1
? a)
∑
n
=
1
∞
1
n
3
/
2
\displaystyle\sum_{n=1}^{\infty} \dfrac{1}{n^{3/2}}
n
=
1
∑
∞
n
3/2
1
b)
∑
n
=
1
∞
e
−
n
n
\displaystyle\sum_{n=1}^{\infty} \dfrac{e^{-n}}{n}
n
=
1
∑
∞
n
e
−
n
c)
∑
n
=
1
∞
sin
n
n
2
\displaystyle\sum_{n=1}^{\infty} \dfrac{\sin n}{n^{2}}
n
=
1
∑
∞
n
2
sin
n
d)
∑
n
=
1
∞
1
n
(
ln
n
+
2
)
\displaystyle\sum_{n=1}^{\infty} \dfrac{1}{n(\ln n+2)}
n
=
1
∑
∞
n
(
ln
n
+
2
)
1
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