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Mathematics
Mathematics
Problem
If the curves
x
2
α
+
y
2
4
=
1
\frac{x^2}{\alpha} + \frac{y^2}{4} = 1
α
x
2
+
4
y
2
=
1
and
y
3
=
16
x
y^3 = 16x
y
3
=
16
x
intersect at right angles, then a value of
α
\alpha
α
is : (1)
4
3
\frac{4}{3}
3
4
(2)
3
4
\frac{3}{4}
4
3
(3)
1
2
\frac{1}{2}
2
1
(4) 2
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