JEE Advanced 2017 Paper 2 Mathematics Q6

Mathematics

Problem

Let S={1,2,3,…,9}S=\{1,2,3,\ldots,9\}. For k=1,2,…,5k=1,2,\ldots,5, let NkN_k be the number of subsets of SS, each containing five elements out of which exactly kk are odd. Then N1+N2+N3+N4+N5=N_1+N_2+N_3+N_4+N_5=

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