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Mathematics
Mathematics
Problem
Solve for
θ
\theta
θ
if
sin
3
θ
=
1
2
\sin 3\theta = \dfrac{1}{2}
sin
3
θ
=
2
1
and
0
<
θ
<
π
6
0<\theta<\dfrac{\pi}{6}
0
<
θ
<
6
π
.
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