Complex Analysis: Theory and Applications · Problem 6.3.7

Complex Integration — Howell & Matthews

Mathematics — Complex Analysis · cauchy-goursat-theorem

Problem

Evaluate ∫C(4z2+4z−3)−1 dz=∫C(2z−1)−1(2z+3)−1 dz\displaystyle\int_C (4z^2+4z-3)^{-1}\,dz = \int_C (2z-1)^{-1}(2z+3)^{-1}\,dz for the following: (a) The circle C=C1+(0)C = C_1^+(0). (b) The circle C=C1+ ⁣(−23)={z:∣z+23∣=1}C = C_1^+\!\left(-\dfrac{2}{3}\right) = \left\{z : \left|z + \dfrac{2}{3}\right| = 1\right\}. (c) The circle C=C3+(0)C = C_3^+(0).

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