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Mathematics
Problem
Let
k
≠
0
k\neq 0
k
=
0
and define three bijective functions:
f
:
R
→
R
f:\mathbb R\to\mathbb R
f
:
R
→
R
,
f
(
x
)
=
k
x
+
1
f(x)=kx+1
f
(
x
)
=
k
x
+
1
;
g
:
R
∖
{
0
}
→
R
∖
{
0
}
g:\mathbb R\setminus\{0\}\to\mathbb R\setminus\{0\}
g
:
R
∖
{
0
}
→
R
∖
{
0
}
,
g
(
x
)
=
1
x
g(x)=\dfrac{1}{x}
g
(
x
)
=
x
1
;
h
:
R
→
R
h:\mathbb R\to\mathbb R
h
:
R
→
R
,
h
(
x
)
=
x
5
h(x)=x^{5}
h
(
x
)
=
x
5
. If
F
=
h
∘
g
∘
f
F=h\circ g\circ f
F
=
h
∘
g
∘
f
, then
F
−
1
(
x
)
F^{-1}(x)
F
−
1
(
x
)
equals a)
x
1
/
5
−
1
k
\dfrac{x^{1/5}-1}{k}
k
x
1/5
−
1
b)
k
x
−
1
/
5
−
1
k\,x^{-1/5}-1
k
x
−
1/5
−
1
c)
x
−
1
/
5
−
1
k
\dfrac{x^{-1/5}-1}{k}
k
x
−
1/5
−
1
d)
1
−
x
1
/
5
k
\dfrac{1-x^{1/5}}{k}
k
1
−
x
1/5
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