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Chemistry
Chemistry
Problem
At 25 °C the solubility product constant of
PbF
2
\text{PbF}_2
PbF
2
is
K
s
p
=
3.2
×
10
−
8
K_{sp}=3.2\times10^{-8}
K
s
p
=
3.2
×
1
0
−
8
. What is the molar solubility of
PbF
2
\text{PbF}_2
PbF
2
in pure water at this temperature? a)
5.1
×
10
−
3
M
5.1\times10^{-3}\,\text{M}
5.1
×
1
0
−
3
M
b)
3.2
×
10
−
8
M
3.2\times10^{-8}\,\text{M}
3.2
×
1
0
−
8
M
c)
2.0
×
10
−
3
M
2.0\times10^{-3}\,\text{M}
2.0
×
1
0
−
3
M
d)
1.8
×
10
−
4
M
1.8\times10^{-4}\,\text{M}
1.8
×
1
0
−
4
M
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