Tea Time Numerical Analysis · Problem 1.2.32

Preliminaries — Leon Brin

Mathematics — Numerical Analysis · taylor-series

Problem

The Taylor series for f(x)=exf(x) = e^x is T(x)=1+x+12!x2+13!x3+14!x4+15!x5+⋯T(x) = 1 + x + \frac{1}{2!}x^2 + \frac{1}{3!}x^3 + \frac{1}{4!}x^4 + \frac{1}{5!}x^5 + \cdots This series converges to f(x)f(x) for all values of xx. In particular, for x=1x = 1, this means that f(1)=T(1)=1+1+12!(1)2+13!(1)3+14!(1)4+⋯f(1) = T(1) = 1 + 1 + \frac{1}{2!}(1)^2 + \frac{1}{3!}(1)^3 + \frac{1}{4!}(1)^4 + \cdots Simplifying this equation, we see that e=1+1+12+16+124+1120+⋯e = 1 + 1 + \frac{1}{2} + \frac{1}{6} + \frac{1}{24} + \frac{1}{120} + \cdots Use Taylor Series to find infinite sums that sum to ((a)) ln⁡(2)\ln(2) ((b)) 2/32/3 ((c)) π/4\pi/4 ((d)) 2\sqrt{2}

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