Physics

Problem

An object is launched from the ground at an angle of

60^{\circ}

and speed

u

. It lands on a table of height

h = 5\,\text{m}

. The horizontal range on the table is measured to be

10\sqrt{3}\,\text{m}

(measured from the launch

x

-coordinate). Calculate the launch speed

u

. (Take

g = 10\,\text{m/s}^{2}

\sin 60^{\circ} = \frac{\sqrt{3}}{2}

\cos 60^{\circ} = \frac{1}{2}

)