Mathematics

Mathematics

Problem

In △ABC\triangle ABC, AB=ACAB = AC. Point DD lies on ACAC with AD=ABAD = AB. If ∠ABD=20∘\angle ABD = 20^\circ, determine ∠ACB\angle ACB. a) 40∘40^{\circ} b) 60∘60^{\circ} c) 20∘20^{\circ} d) 140∘140^{\circ}

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