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Mathematics
Problem
The temperature
T
T
T
(in
∘
C
^{\circ}\text{C}
∘
C
) of a cooling liquid is a differentiable function of time
t
t
t
(in minutes). A measurement shows
T
′
(
5
)
=
−
0.4
∘
C
/
min
T'(5)=-0.4\,^{\circ}\text{C}/\text{min}
T
′
(
5
)
=
−
0.4
∘
C
/
min
. Describe the practical meaning of this value.
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