Mathematics

Problem

The area (in sq. units) of the smaller portion enclosed between the curves,

x^2 + y^2 = 4

and

y^2 = 3x

, is: (1)

\frac{1}{\sqrt{3}} + \frac{2\pi}{3}

(2)

\frac{1}{\sqrt{3}} + \frac{4\pi}{3}

(3)

\frac{1}{2\sqrt{3}} + \frac{2\pi}{3}

(4)

\frac{1}{2\sqrt{3}} + \frac{\pi}{3}