Mathematics

Mathematics

Problem

If tan⁡γ=sec⁡αsec⁡β+tan⁡αtan⁡β\tan \gamma = \sec \alpha \sec \beta + \tan \alpha \tan \beta , then the highest value of cos⁡2γ\cos 2\gamma is: (a) −1-1 (b) 12\frac{1}{2} (c) −12-\frac{1}{2} (d) 00

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