Physics

Problem

A particle of mass

m

is projected with a velocity

v

making an angle of

45^\circ

with the horizontal. Find the magnitude of the angular momentum of the projectile about the point of projection when the particle is at its maximum height

h

. a. zero b.

\frac{mv^3}{4\sqrt{2}g}

\frac{mv^3}{\sqrt{2}g}

m\sqrt{2gh^3}

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