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Mathematics
Mathematics
Problem
The curve
r
=
4
cos
θ
r=4\cos\theta
r
=
4
cos
θ
encloses a finite region in the plane. Which of the following definite integrals correctly represents the area of that region? a)
∫
−
π
/
2
π
/
2
(
4
cos
θ
)
2
d
θ
\displaystyle \int_{-\pi/2}^{\pi/2}(4\cos\theta)^2\,d\theta
∫
−
π
/2
π
/2
(
4
cos
θ
)
2
d
θ
b)
1
2
∫
0
π
/
2
(
4
cos
θ
)
2
d
θ
\displaystyle \tfrac12\int_{0}^{\pi/2}(4\cos\theta)^2\,d\theta
2
1
∫
0
π
/2
(
4
cos
θ
)
2
d
θ
c)
1
2
∫
−
π
/
2
π
/
2
(
4
cos
θ
)
2
d
θ
\displaystyle \tfrac12\int_{-\pi/2}^{\pi/2}(4\cos\theta)^2\,d\theta
2
1
∫
−
π
/2
π
/2
(
4
cos
θ
)
2
d
θ
d)
1
2
∫
0
π
(
4
cos
θ
)
2
d
θ
\displaystyle \tfrac12\int_{0}^{\pi}(4\cos\theta)^2\,d\theta
2
1
∫
0
π
(
4
cos
θ
)
2
d
θ
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