A mixture of 3.5 mol of TiCl4 and 2.5 mol of TiCl2 was allowed to react in a vessel of volume 2 dm3. At equilibrium, it was found that the mixture contained 1.4 mol of TiCl3.
The equation for the reaction is as follows:
TiCl2(g)+TiCl4(g)⇌2TiCl3(s)
Calculate the equilibrium constant for this reaction.