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Mathematics
Problem
∫
x
e
−
1
+
e
x
−
1
x
e
+
e
x
d
x
=
\int \frac{x^{e-1} + e^{x-1}}{x^e + e^x}\,dx =
∫
x
e
+
e
x
x
e
−
1
+
e
x
−
1
d
x
=
A)
log
(
x
e
+
e
x
)
+
c
\log(x^e + e^x) + c
lo
g
(
x
e
+
e
x
)
+
c
B)
e
log
(
x
e
+
e
x
)
+
c
e\log(x^e + e^x) + c
e
lo
g
(
x
e
+
e
x
)
+
c
C)
1
e
log
(
x
e
+
e
x
)
+
c
\frac{1}{e}\log(x^e + e^x) + c
e
1
lo
g
(
x
e
+
e
x
)
+
c
D) None of these A)
log
(
x
e
+
e
x
)
+
c
\log(x^e + e^x) + c
lo
g
(
x
e
+
e
x
)
+
c
B)
e
log
(
x
e
+
e
x
)
+
c
e\log(x^e + e^x) + c
e
lo
g
(
x
e
+
e
x
)
+
c
C)
1
e
log
(
x
e
+
e
x
)
+
c
\frac{1}{e}\log(x^e + e^x) + c
e
1
lo
g
(
x
e
+
e
x
)
+
c
D) None of these
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