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Problem
Problem
The value of
lim
x
→
0
{
sin
2
π
2
−
a
x
2
−
a
x
}
sec
2
π
2
−
b
x
\lim_{x \to 0} \left\{ \frac{\sin^2 \frac{\pi}{2-ax}}{2-ax} \right\}^{\sec^2 \frac{\pi}{2-bx}}
x
→
0
lim
{
2
−
a
x
sin
2
2
−
a
x
π
}
s
e
c
2
2
−
b
x
π
is equal to a.
e
−
a
/
b
e^{-a/b}
e
−
a
/
b
b.
e
−
a
2
/
b
2
e^{-a^2/b^2}
e
−
a
2
/
b
2
c.
a
2
a
/
b
a^{2a/b}
a
2
a
/
b
d.
e
4
a
/
b
e^{4a/b}
e
4
a
/
b
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