General Relativity: An Introduction for Physicists · Problem 13.10

The Kerr geometry — Hobson, Efstathiou & Lasenby

Physics · kerr-equatorial-contravariant-metric

Problem

Show that, in the equatorial plane θ=π/2\theta = \pi/2 of the Kerr geometry, the contravariant metric components in Boyer–Lindquist coordinates are gtt=1c2Δ(r2+a2+2μa2r),gtϕ=2μacrΔ,g^{tt} = \frac{1}{c^2 \Delta}\left(r^2 + a^2 + \frac{2\mu a^2}{r}\right), \qquad g^{t\phi} = \frac{2\mu a}{cr\Delta}, grr=−Δr2,gϕϕ=−1Δ(1−2μr).g^{rr} = -\frac{\Delta}{r^2}, \qquad g^{\phi\phi} = -\frac{1}{\Delta}\left(1 - \frac{2\mu}{r}\right).

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