Problem

Problem

5 g of water at 30∘C30^\circ\text{C} and 5 g of ice at −20∘C-20^\circ\text{C} are mixed together in a calorimeter. Find the final temperature of mixture. Water equivalent of calorimeter is negligible, specific heat of ice = 0.5 cal/g⋅∘C0.5 \text{ cal/g}\cdot^\circ\text{C} and latent heat of ice = 80 cal/g80 \text{ cal/g} .

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