Problem

Problem

When 0.0222 mol of decane, C10H22\text{C}_{10}\text{H}_{22} , is combusted in an excess of oxygen, the heat energy change of the surroundings is 145 kJ. Use this information to calculate the enthalpy change of the reaction given below: 2C10H22(l)+31O2(g)→20CO2(g)+22H2O(l)ΔH⊖=?2 \text{C}_{10}\text{H}_{22}(\text{l}) + 31 \text{O}_2(\text{g}) \rightarrow 20 \text{CO}_2(\text{g}) + 22 \text{H}_2\text{O}(\text{l}) \quad \Delta H^\ominus = ?

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