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Mathematics
Mathematics
Problem
Let
f
(
x
)
=
x
+
3
log
(
x
−
2
)
f(x) = x + 3 \log(x-2)
f
(
x
)
=
x
+
3
lo
g
(
x
−
2
)
and
g
(
x
)
=
x
+
5
log
(
x
−
1
)
g(x) = x + 5 \log(x-1)
g
(
x
)
=
x
+
5
lo
g
(
x
−
1
)
, then the set of
x
x
x
satisfying the inequality
f
′
(
x
)
<
g
′
(
x
)
f'(x) < g'(x)
f
′
(
x
)
<
g
′
(
x
)
is a.
(
2
,
7
/
2
)
(2, 7/2)
(
2
,
7/2
)
b.
(
1
,
2
)
∪
(
7
/
2
,
∞
)
(1, 2) \cup (7/2, \infty)
(
1
,
2
)
∪
(
7/2
,
∞
)
c.
(
2
,
∞
)
(2, \infty)
(
2
,
∞
)
d.
(
7
/
2
,
∞
)
(7/2, \infty)
(
7/2
,
∞
)
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