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Mathematics
Mathematics
Problem
If
sin
θ
−
6
cos
θ
=
7
cos
θ
\sin \theta - \sqrt{6} \cos \theta = \sqrt{7} \cos \theta
sin
θ
−
6
cos
θ
=
7
cos
θ
. Prove that
cos
θ
+
6
sin
θ
−
7
sin
θ
=
0
\cos \theta + \sqrt{6} \sin \theta - \sqrt{7} \sin \theta = 0
cos
θ
+
6
sin
θ
−
7
sin
θ
=
0
.
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