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Mathematics
Problem
Let
x
=
t
2
+
1
x=t^{2}+1
x
=
t
2
+
1
and
y
=
t
3
−
3
t
y=t^{3}-3t
y
=
t
3
−
3
t
. Find
d
2
y
d
x
2
\dfrac{d^{2}y}{dx^{2}}
d
x
2
d
2
y
at
t
=
1
t=1
t
=
1
. a)
3
4
\dfrac{3}{4}
4
3
b)
3
2
\dfrac{3}{2}
2
3
c)
−
3
2
-\dfrac{3}{2}
−
2
3
d)
12
12
12
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