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Mathematics
Mathematics
Problem
Let
E
=
216
p
7
q
5
3
24
p
2
q
E = \dfrac{\sqrt[3]{216p^{7}q^{5}}}{\sqrt{24p^{2}q}}
E
=
24
p
2
q
3
216
p
7
q
5
, where
p
,
q
>
0
p,q>0
p
,
q
>
0
. a. (i) Simplify the numerator
216
p
7
q
5
3
\sqrt[3]{216p^{7}q^{5}}
3
216
p
7
q
5
. b. (ii) Simplify the denominator
24
p
2
q
\sqrt{24p^{2}q}
24
p
2
q
. c. (iii) Hence, express
E
E
E
in its simplest radical form.
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