Mathematics

Mathematics

Problem

Let E=216p7q5324p2qE = \dfrac{\sqrt[3]{216p^{7}q^{5}}}{\sqrt{24p^{2}q}}, where p,q>0p,q>0. a. (i) Simplify the numerator 216p7q53\sqrt[3]{216p^{7}q^{5}}. b. (ii) Simplify the denominator 24p2q\sqrt{24p^{2}q}. c. (iii) Hence, express EE in its simplest radical form.

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