Abstract Algebra: Theory and Applications · Problem 10.4.14

Homomorphisms — Thomas Judson

Mathematics — Abstract Algebra · commutator-subgroup

Problem

Let GG be a group and let G′=⟨aba−1b−1⟩G' = \langle aba^{-1}b^{-1} \rangle; that is, G′G' is the subgroup of all finite products of elements in GG of the form aba−1b−1aba^{-1}b^{-1}. The subgroup G′G' is called the commutator subgroup of GG. (a) Show that G′G' is a normal subgroup of GG. (b) Let NN be a normal subgroup of GG. Prove that G/NG/N is abelian if and only if NN contains the commutator subgroup of GG. Hint. (a) Let g∈Gg \in G and h∈G′h \in G'. If h=aba−1b−1h = aba^{-1}b^{-1}, then ghg−1=gaba−1b−1g−1=(gag−1)(gbg−1)(ga−1g−1)(gb−1g−1)=(gag−1)(gbg−1)(gag−1)−1(gbg−1)−1.\begin{aligned} ghg^{-1} &= gaba^{-1}b^{-1}g^{-1} \\ &= (gag^{-1})(gbg^{-1})(ga^{-1}g^{-1})(gb^{-1}g^{-1}) \\ &= (gag^{-1})(gbg^{-1})(gag^{-1})^{-1}(gbg^{-1})^{-1}. \end{aligned} We also need to show that if h=h1⋯hnh = h_1 \cdots h_n with hi=aibiai−1bi−1h_i = a_i b_i a_i^{-1} b_i^{-1}, then ghg−1ghg^{-1} is a product of elements of the same type. However, ghg−1=gh1⋯hng−1=(gh1g−1)(gh2g−1)⋯(ghng−1)ghg^{-1} = gh_1 \cdots h_n g^{-1} = (gh_1 g^{-1})(gh_2 g^{-1}) \cdots (gh_n g^{-1}).

Browse the problem library