If f(x)={a∣x∣+x2−2(sin⁡∣x∣)(cos⁡∣x∣)x,x≠0b,x=0f(x) = \begin{cases} \frac{a|x|+x^2-2(\sin |x|)(\cos |x|)}{x}, & x \neq 0 \\ b, & x = 0 \end{cases}…

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If f(x)={a∣x∣+x2−2(sin⁡∣x∣)(cos⁡∣x∣)x,x≠0b,x=0f(x) = \begin{cases} \frac{a|x|+x^2-2(\sin |x|)(\cos |x|)}{x}, & x \neq 0 \\ b, & x = 0 \end{cases} is continuous at x=0x = 0, then a+ba + b is equal to

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