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Problem
Problem
If
f
(
x
)
=
sin
log
x
f(x) = \sin \log x
f
(
x
)
=
sin
lo
g
x
, then the value of
f
(
x
y
)
+
f
(
x
y
)
−
2
f
(
x
)
⋅
cos
(
log
y
)
f(xy) + f\left(\frac{x}{y}\right) - 2f(x) \cdot \cos(\log y)
f
(
x
y
)
+
f
(
y
x
)
−
2
f
(
x
)
⋅
cos
(
lo
g
y
)
is equal to a.
1
1
1
b.
0
0
0
c.
−
1
-1
−
1
d.
sin
log
x
⋅
cos
log
y
\sin \log x \cdot \cos \log y
sin
lo
g
x
⋅
cos
lo
g
y
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