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Mathematics
Mathematics
Problem
For the parametric curve
x
=
t
−
sin
t
,
y
=
1
−
cos
t
x = t - \sin t,\; y = 1 - \cos t
x
=
t
−
sin
t
,
y
=
1
−
cos
t
with
0
<
t
<
2
π
0 < t < 2\pi
0
<
t
<
2
π
, the slope of the tangent equals
1
2
\dfrac{1}{2}
2
1
at which of the following values of
t
t
t
? a)
t
=
π
−
2
tan
−
1
2
t = \pi - 2\tan^{-1}2
t
=
π
−
2
tan
−
1
2
b)
t
=
tan
−
1
2
t = \tan^{-1} 2
t
=
tan
−
1
2
c)
t
=
2
tan
−
1
2
t = 2\tan^{-1} 2
t
=
2
tan
−
1
2
d)
t
=
2
tan
−
1
(
1
2
)
t = 2\tan^{-1}\!\bigl(\tfrac{1}{2}\bigr)
t
=
2
tan
−
1
(
2
1
)
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