Mathematics

Mathematics

Problem

If ADAD is median of △ABC\triangle ABC and PP is a point on ACAC such that ar(△ADP):ar(△ABD)=4:5ar(\triangle ADP) : ar(\triangle ABD) = 4 : 5 , then ar(△PDC):ar(△ABC)ar(\triangle PDC) : ar(\triangle ABC) is (A) 1 : 10 (B) 10 : 1 (C) 1 : 3 (D) 3 : 1

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