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Mathematics
Problem
∫
d
x
x
+
x
log
x
=
\int \frac{dx}{x + x\log x} =
∫
x
+
x
l
o
g
x
d
x
=
A)
log
(
1
+
log
x
)
+
c
\log(1 + \log x) + c
lo
g
(
1
+
lo
g
x
)
+
c
B)
log
log
(
1
+
log
x
)
+
c
\log\log(1 + \log x) + c
lo
g
lo
g
(
1
+
lo
g
x
)
+
c
C)
log
x
+
log
(
log
x
)
+
c
\log x + \log(\log x) + c
lo
g
x
+
lo
g
(
lo
g
x
)
+
c
D) None of these A)
log
(
1
+
log
x
)
+
c
\log(1 + \log x) + c
lo
g
(
1
+
lo
g
x
)
+
c
B)
log
log
(
1
+
log
x
)
+
c
\log\log(1 + \log x) + c
lo
g
lo
g
(
1
+
lo
g
x
)
+
c
C)
log
x
+
log
(
log
x
)
+
c
\log x + \log(\log x) + c
lo
g
x
+
lo
g
(
lo
g
x
)
+
c
D) None of these
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