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Problem
Problem
The value of
lim
x
→
π
/
2
[
x
2
]
log
(
sin
x
)
\lim_{x \to \pi/2} \frac{\left[ \frac{x}{2} \right]}{\log(\sin x)}
lim
x
→
π
/2
l
o
g
(
s
i
n
x
)
[
2
x
]
is equal to a. 0 b. 1 c. -1 d. doesn't exist
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