Mathematics

Mathematics

Problem

Three vectors a\mathbf{a} ( ∣a∣≠0|\mathbf{a}| \neq 0 ), b\mathbf{b} and c\mathbf{c} are such that a×b=3a×c\mathbf{a} \times \mathbf{b} = 3\mathbf{a} \times \mathbf{c} . Also, ∣a∣=∣b∣=1|\mathbf{a}| = |\mathbf{b}| = 1 and ∣c∣=13|\mathbf{c}| = \frac{1}{3} . If the angle between b\mathbf{b} and c\mathbf{c} is 60∘60^\circ , then a. b=3c+a\mathbf{b} = 3\mathbf{c} + \mathbf{a} b. b=3c−a\mathbf{b} = 3\mathbf{c} - \mathbf{a} c. a=6c+2b\mathbf{a} = 6\mathbf{c} + 2\mathbf{b} d. a=6c−2b\mathbf{a} = 6\mathbf{c} - 2\mathbf{b}

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