JEE Advanced 2015 Paper 2 Mathematics Q14

Mathematics

Problem

Let f,g:[−1,2]→Rf,g:[-1,2]\to\mathbb R be continuous functions which are twice differentiable on the interval (−1,2)(-1,2). Let the values of ff and gg at the points −1-1, 00 and 22 be as given in the following table: x=−1x=0x=2f(x)360g(x)01−1\begin{array}{c|ccc}&x=-1&x=0&x=2\\\hline f(x)&3&6&0\\g(x)&0&1&-1\end{array} In each of the intervals (−1,0)(-1,0) and (0,2)(0,2) the function (f−3g)′′(f-3g)'' never vanishes. Then the correct statement(s) is(are)

Browse the problem library