Let f,g:[−1,2]→R be continuous functions which are twice differentiable on the interval (−1,2). Let the values of f and g at the points −1, 0 and 2 be as given in the following table: f(x)g(x)x=−130x=061x=20−1 In each of the intervals (−1,0) and (0,2) the function (f−3g)′′ never vanishes. Then the correct statement(s) is(are)