Mathematics

Problem

For

f(x)=\sin x

on the interval

[0,\pi]

, which value of

c

(0,\pi)

satisfies

f'(c)=\dfrac{f(\pi)-f(0)}{\pi-0}

? a)

\dfrac{\pi}{4}

\dfrac{\pi}{2}

\dfrac{\pi}{6}

\dfrac{2\pi}{3}