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Problem
Problem
- Obtain the binding energy of a nitrogen nucleus from the following data :
m
H
=
1.00783
u
,
m
N
=
1.00867
u
,
m
(
7
14
N
)
=
14.00307
u
m_H = 1.00783 \text{ u}, m_N = 1.00867 \text{ u}, m({}_{7}^{14}\text{N}) = 14.00307 \text{ u}
m
H
=
1.00783
u
,
m
N
=
1.00867
u
,
m
(
7
14
N
)
=
14.00307
u
Give your answer in units of MeV. [ Remember
1
u
=
931.5
MeV
/
c
2
1 \text{ u} = 931.5 \text{ MeV}/c^2
1
u
=
931.5
MeV
/
c
2
]
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