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Callen H.B - Thermodynamics And An Introduction To Thermostatistics · Problem 7.5-4
FIRST-ORDER PHASE TRANSITIONS
Physics — Statistical Mechanics · magnetic-heat-capacity-susceptibility
Problem Show that
C B e − C I = μ 0 2 T χ T 2 ( ∂ I ∂ T ) B e C_{B_e} - C_I = \frac{\mu_0^2 T}{\chi_T^2}\left(\frac{\partial I}{\partial T}\right)_{B_e} C B e − C I = χ T 2 μ 0 2 T ( ∂ T ∂ I ) B e
and
C B e C I = χ T χ S \frac{C_{B_e}}{C_I} = \frac{\chi_T}{\chi_S} C I C B e = χ S χ T
where C B e C_{B_e} C B e and C I C_I C I are heat capacities and χ T \chi_T χ T and χ s \chi_s χ s are susceptibilities: χ T ≡ μ 0 ( ∂ I / ∂ B e ) T \chi_T \equiv \mu_0(\partial I/\partial B_e)_T χ T ≡ μ 0 ( ∂ I / ∂ B e ) T .
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