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Mathematics
Problem
Suppose
7
x
−
9
(
x
+
3
)
(
x
−
4
)
=
A
x
+
3
+
B
x
−
4
\dfrac{7x-9}{(x+3)(x-4)}=\dfrac{A}{x+3}+\dfrac{B}{x-4}
(
x
+
3
)
(
x
−
4
)
7
x
−
9
=
x
+
3
A
+
x
−
4
B
. What is the value of
A
A
A
? a)
19
7
\dfrac{19}{7}
7
19
b)
30
7
\dfrac{30}{7}
7
30
c)
−
19
7
-\dfrac{19}{7}
−
7
19
d)
−
30
7
-\dfrac{30}{7}
−
7
30
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