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Mathematics
Problem
Consider the parametric equations
x
=
t
2
+
1
x=t^{2}+1
x
=
t
2
+
1
and
y
=
t
3
−
3
t
y=t^{3}-3t
y
=
t
3
−
3
t
. What is the value of
d
2
y
d
x
2
\dfrac{d^{2}y}{dx^{2}}
d
x
2
d
2
y
at
t
=
1
t=1
t
=
1
? a)
0.75
0.75
0.75
b)
1.5
1.5
1.5
c)
−
1.5
-1.5
−
1.5
d)
3
3
3
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