Mathematics

Problem

Let

g(x)=\displaystyle\int_{0}^{x}e^{-t^{2}}\,dt

. In the Maclaurin series for

g

, the coefficient of

x^{5}

is a)

-\dfrac{1}{10}

\dfrac{1}{5}

\dfrac{1}{8}

\dfrac{1}{10}