Physics

Problem

This equation shows a nuclear process:

{}_{92}^{235}\text{U} + {}_{0}^{1}\text{n} \rightarrow {}_{92}^{236}\text{U} \rightarrow {}_{56}^{144}\text{Ba} + {}_{36}^{89}\text{Kr} + 3{}_{0}^{1}\text{n} \quad .

The masses of the various particles are

{}_{92}^{236}\text{U} = 236.0526 \text{ u} ; \quad {}_{56}^{144}\text{Ba} = 143.92292 \text{ u} ; \\ {}_{36}^{89}\text{Kr} = 88.91781 \text{ u} ; \quad {}_{0}^{1}\text{n} = 1.008665 \text{ u} .