Mathematics

Mathematics

Problem

Answer the following questions related to the equation tan⁡θ=−1\tan \theta = -1 for 0≤θ<2π0 \le \theta < 2\pi. a. (i) Explain why θ=π2\theta = \dfrac{\pi}{2} and θ=3π2\theta = \dfrac{3\pi}{2} cannot satisfy the given equation. b. (ii) Using the signs of tangent in the four quadrants, identify the quadrants in which the solutions of tan⁡θ=−1\tan \theta = -1 will lie. c. (iii) Determine the exact values of θ\theta in the interval 0≤θ<2π0 \le \theta < 2\pi that satisfy tan⁡θ=−1\tan \theta = -1, and justify your answer.

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