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Physics
Physics
Problem
A concave mirror of focal length 12 cm forms a virtual, erect image that is twice the height of the 2.0 cm tall object. What is the object distance from the mirror (u) according to the Cartesian sign convention? a)
+
6
cm
+6\ \text{cm}
+
6
cm
b)
−
6
cm
-6\ \text{cm}
−
6
cm
c)
−
8
cm
-8\ \text{cm}
−
8
cm
d)
−
18
cm
-18\ \text{cm}
−
18
cm
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