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Mathematics
Mathematics
Problem
Consider three vectors
p
=
i
+
j
+
k
\mathbf{p} = \mathbf{i} + \mathbf{j} + \mathbf{k}
p
=
i
+
j
+
k
,
q
=
2
i
+
4
j
−
k
\mathbf{q} = 2\mathbf{i} + 4\mathbf{j} - \mathbf{k}
q
=
2
i
+
4
j
−
k
and
r
=
i
+
j
+
3
k
\mathbf{r} = \mathbf{i} + \mathbf{j} + 3\mathbf{k}
r
=
i
+
j
+
3
k
. If
p
\mathbf{p}
p
,
q
\mathbf{q}
q
and
r
\mathbf{r}
r
denotes the position vector of three non-collinear points, then the equation of the plane containing these points is a.
2
x
−
3
y
+
1
=
0
2x - 3y + 1 = 0
2
x
−
3
y
+
1
=
0
b.
x
−
3
y
+
2
z
=
0
x - 3y + 2z = 0
x
−
3
y
+
2
z
=
0
c.
3
x
−
y
+
z
−
3
=
0
3x - y + z - 3 = 0
3
x
−
y
+
z
−
3
=
0
d.
3
x
−
y
−
2
=
0
3x - y - 2 = 0
3
x
−
y
−
2
=
0
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