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Mathematics
Problem
The shortest distance between the lines
x
+
2
1
=
y
−
2
=
z
−
5
2
and
x
−
4
1
=
y
−
1
2
=
z
+
3
0
is
\frac{x+2}{1} = \frac{y}{-2} = \frac{z-5}{2} \text{ and } \frac{x-4}{1} = \frac{y-1}{2} = \frac{z+3}{0} \text{ is}
1
x
+
2
=
−
2
y
=
2
z
−
5
and
1
x
−
4
=
2
y
−
1
=
0
z
+
3
is
[April 10, 2023 (I)] (a) 6 (b) 9 (c) 7 (d) 8
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