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Chemistry
Chemistry
Problem
On the basis of reaction :
4
3
A
l
+
O
2
→
2
3
A
l
2
O
3
\frac{4}{3}Al + O_2 \rightarrow \frac{2}{3}Al_2O_3
3
4
A
l
+
O
2
→
3
2
A
l
2
O
3
;
Δ
G
=
−
827
kJ mol
−
1
\Delta G = -827 \text{ kJ mol}^{-1}
Δ
G
=
−
827
kJ mol
−
1
of
O
2
O_2
O
2
, the minimum emf required to carry out electrolysis of
A
l
2
O
3
Al_2O_3
A
l
2
O
3
is: a. 6.42 V b. 8.56 V c. 2.14 V d. 4.28 V
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