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Mathematics
Mathematics
Problem
In the complex plane, consider the parallelogram formed by the points
0
,
z
,
1
z
0, z, \frac{1}{z}
0
,
z
,
z
1
and
z
+
1
z
z + \frac{1}{z}
z
+
z
1
having area
12
13
\frac{12}{13}
13
12
square units and the real part of 'z' is positive. If the smallest possible value of
∣
z
+
1
z
∣
|z + \frac{1}{z}|
∣
z
+
z
1
∣
is 'p', then
13
p
2
4
\frac{13p^2}{4}
4
13
p
2
is - - -
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