Let the major axis of a standard ellipse equals the transverse axis of a standard hyperbola and their director circles have radius equal to 2R and R respectively. If e1 and e2 are the eccentricities of the ellipse and hyperbola, then the correct relation is
a. 4e12−e22=6
b. e12−4e22=2
c. 4e22−e12=6
d. e22−4e12=2