Mathematics

Mathematics

Problem

If cos⁡−1xa+cos⁡−1yb=θ\cos^{-1} \frac{x}{a} + \cos^{-1} \frac{y}{b} = \theta, then show that x2a2+y2b2−2xyabcos⁡θ=sin⁡2θ\frac{x^2}{a^2} + \frac{y^2}{b^2} - \frac{2xy}{ab} \cos \theta = \sin^2 \theta.

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